Question 1206036
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theta = {{{theta}}} = angle of elevation
{{{
drawing(400,400,-5,5,-5,5,

line(-3,-2,3,-2),line(3,-2,3,3),line(3,3,-3,-2),
line(2.6,-2,2.6,-1.6),line(2.6,-1.6,3,-1.6),
locate(-1.8,1,"hypotenuse"),locate(3.2,1,"opposite"),locate(-1,-2.5,"adjacent"),locate(-0.92,-3.08,"16"),locate(3.66,0.1,"48"),

locate(-4.5,-4.5,matrix(1,4,"Diagram","not","to","scale")),

locate(-2.1,-1.5,theta)
)
}}}


tan(angle) = opposite/adjacent
tan(theta) = 48/16
tan(theta) = 3
theta = *[tex \large \tan^{-1}(3)] = arctan(3) = <font color=red>71.565051 degrees approximately</font>
Round this value however needed.
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