Question 1206042
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x = some amount of money invested at 8% interest rate
2x+22000 = amount invested at 12%


A = 0.08x = amount of interest earned from the 8% account
B = 0.12*(2x+22000) = interest earned from the 12% account
Each duration is for 1 year. 
I'll assume simple interest is used, and not compound interest.


A+B = total interest earned for 1 year
A+B = 0.08x+0.12*(2x+22000) = 30800


Let's isolate x.
0.08x+0.12*(2x+22000) = 30800
0.08x+0.12*(2x)+0.12*(22000) = 30800
0.08x+0.24x+2640 = 30800
0.32x+2640 = 30800
0.32x = 30800-2640 
0.32x = 28160 
x = 28160/0.32 
x = <font color=red size=4>$88,000</font> was invested at 8%


And,
2x+22000 = 2*88000+22000 = <font color=red size=4>$198,000</font> was invested at 12%


Check:
0.08*88000 + 0.12*198000 = 30800
The answers are confirmed.
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