Question 1206034

there are {{{11}}} total numbers between {{{1}}} and {{{11}}}
there are {{{7}}} numbers greater than {{{4}}}, and {{{6}}} numbers less than {{{7}}} 
 then the probability that the first value will be more than {{{4}}} and the second will be less than {{{7}}} is:

 {{{P= (7/11) (6/11)=42/121=0.347107438}}}