Question 115608
5a - 12 OVER a squared - 8a + 15 MINUS 3a - 2 OVER a squared - 8a + 15
:
Assume you mean:
{{{((5a-12))/((a^2-8a+15))}}} - {{{((3a-2))/((a^2-8a+15))}}}
:
They have the same denominators, so you can write it:
{{{((5a-12)-(3a-2))/((a^2-8a+15))}}}
:
Remove the brackets, remember a minus outside the brackets changes the signs
{{{(5a-12-3a+2)/((a^2-8a+15))}}}
:
In the numerator, do the math on like terms and you have;
{{{(2a-10)/((a^2-8a+15))}}}
:
We can factor both the numerator and the denominator here:
{{{(2(a-5))/((a-3)(a-5))}}}
:
You can see that the (a-5)'s will cancel, leaving us with:
{{{2/(a-3)}}}