Question 1206008
.
If 10% of cars approaching an intersection leg turn left, what is the probability 
that at least one out of three cars chosen at random will turn left?
~~~~~~~~~~~~~~~~~~~~


<pre>
Then the probability that NO ONE of three cars will turn left is  {{{0.9^3}}} = 0.729.


Respectively, the probability that at least one of three cars will turn left is the complement to it

    P = 1 - {{{0.9^3}}} = 1 - 0.729 = 0.271.    <U>ANSWER</U>
</pre>

Solved.