Question 1206008

this is a binomial distribution 

given:

{{{n = 3}}} 
{{{p = 0.10}}}

the probability that at least one out of three:

{{{P(1<= x <=3) }}}

= {{{1 - P(x = 0)}}}

= {{{1 - 0.9^3}}}

= {{{1 - 0.7290}}}

= {{{0.27}}}