Question 1205980
<pre>
If the problem had been this way:

A school contains 357 boys and 323 girls.
If 2 students are chosen at random, what is the probability of choosing 
a boy and a girl.

The numerator of the probability would be the number of successful ways:
Choose a boy 357 ways, then choose a girl 357 ways.  323x357 = 115311 
successful ways.

The denominator of the probability would be the number of ways any two 
students could be chosen.  That's C(357+323,2) = C(680,2) = 230869

So the probability would be 115311/230860 = 969/1940 = 0.4994845361, very 
close to 0.5.

Edwin</pre>