Question 1205969


an equation of the line is:

{{{y=mx+b}}} 

where {{{m}}} is a slope and {{{b}}} is y-intercept


since given that line passes through points ({{{-3}}}, {{{2}}}) and ({{{-2}}},{{{ -1}}}), use them to find a slope

{{{m=(-1-2)/(-2-(-3))}}}

{{{m=-3/(-2+3)}}}

{{{m=-3/1}}}

{{{m=-3}}}

so far your equation is

{{{y=-3x+b}}} ....use one point,({{{-3}}}, {{{2}}}), to calculate {{{b}}}

{{{2=-3(-3)+b}}}

{{{2=9+b}}}

{{{2-9=b}}}

{{{b=-7}}}

your equation is:

{{{y=-3x-7}}}


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(-3,2,.12),circle(-2,-1,.12),
locate(-3,2,p(-3,2)),locate(-2,-1,p(-2,-1)),
graph( 600, 600, -10, 10, -10, 10, -3x-7)) }}}