Question 1205956
The third term of a g.p is 12 and the first term is 48.find the sum of the first 11 terms

let a 1  be the first term,

r  the common ratio,

n  the term number.

The nth term of GP is tn = ar^(n-1)

third term of a  G P is 12 

t3 = 12 = 48 * r^2

12/48 = r^2

1/4 = r^2

r =  1/2

Sn sum of n terms of G P  ={{{ (a1*(r^n -1))/ (r -1)}}}



{{{ S 11 = (48*((1/2)^11 -1))/ ((1/2)-1)}},

=96 (ROUNDED OFF)



the terms are

48,  24, 12, 6, 3, 3/2, 3/4, 3/8, 3/16, 3/32, 3/64