Question 1205937
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bag contains 44 U.S. quarters and six Canadian quarters. The coins are identical in size) 
If six quarters are randomly picked from the bag, what is the probability of getting at least 
one Canadian quarter? (Round your answer to one decimal place)
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In all, there are 44 + 6 = 50 coins.


The number of all possible different sextuples of coins is  {{{C[50]^6}}} = {{{(50*49*48*47*46*45)/(1*2*3*4*5*6)}}} = 15890700.


The number of all possible different sextuples consisting of US quarters only is  {{{C[44]^6}}} = {{{(44*43*42*41*40*39)/(1*2*3*4*5*6)}}} = 7059052.


The difference of these numbers,  15890700 - 7059052 = 8831648, represents those sextuples that contain at least one Canadian quarter.


Therefore, the ratio  P = {{{8831648/15890700}}} = 0.5558  (rounded) is the probability under the problem's question.


Rounded to one decimal, P = 0.6, is the final answer.
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Solved.