Question 1205934
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<pre>

{{{1/cot(x)}}} = {{{sin(x)/cos(x)}}} = +/- {{{sin(x)/sqrt(1-sin^2(x))}}}.


In QI,    {{{1/cot(x)}}} = {{{sin(x)/sqrt(1-sin^2(x))}}}. 


In QII,   {{{1/cot(x)}}} = -{{{sin(x)/sqrt(1-sin^2(x))}}}. 


In QIII,  {{{1/cot(x)}}} = -{{{sin(x)/sqrt(1-sin^2(x))}}}. 


In QIV,   {{{1/cot(x)}}} = {{{sin(x)/sqrt(1-sin^2(x))}}}. 
</pre>

Solved.


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The answer by @MathLover1 is partly incomplete and partly incorrect.