Question 1205889


{{{H(x)= log(2,(x+8))}}}

to find x-intercept, set {{{H(x)=0}}}

{{{0= log(2,(x+8))}}}...change to base {{{10}}}

{{{0= log((x+8))/log(2)}}}

{{{log((x+8))=0}}}.....in base {{{10}}},{{{ log(1)=0}}}

{{{log((x+8))=log(1)}}}

{{{x+8=1}}}

{{{x=1-8}}}

{{{x=-7}}}


to find y-intercept, set {{{x=0}}}

{{{H(x)= log(2,(0+8))}}}

{{{H(x)= log(2,(8))}}}...change to base {{{10}}}

{{{H(x)= log((8))/log(2)}}}

{{{H(x)= log((2^3))/log(2)}}}

{{{H(x)= 3log(2)/log(2)}}}

{{{H(x)= 3}}}


{{{ graph( 600, 600, -10, 10, -10, 10, log(2,(x+8))) }}}