Question 115787
{{{2x + 3y = 1}}}
{{{5x + 3y = 16}}}
multiply the 1st by -1
{{{-2x - 3y = -1}}}
{{{5x + 3y = 16}}}
add
{{{3x = 15}}}
{{{x = 5}}}
substitute
{{{2x + 3y = 1}}}
{{{2*5 + 3y = 1}}}
{{{3y = -9}}}
{{{y = -3}}}
The solution is (5,-3)
It's a unique solution