Question 1205719
<pre>
Katie has a collection of nickels, dimes and quarters with a total value of $6.80. There are 5 more dimes than nickels and 6 more quarters than nickels, how many of each coin does she have?

Let number of nickels be N
Then, number of dimes and quarters = N + 5, and N + 6, respectively

Value of nickels: .05N
Value of dimes:    .1(N + 5) = .1N + .5
Value of quarters:.25(N + 6) = .25N + 1.5 

As total value is 6.80, we get:  .05N + .1N + .5 + .25N + 1.5 = 6.8
                                                      .4N + 2 = 6.8
                                                          .4N = 4.8
                                     Number of nickels, or {{{highlight_green(matrix(1,7, N, "=", 4.8/.4, "=", 48/4, "=", highlight(12)))}}} 

Now, calculate number of dimes (N + 5), and number of quarters (N + 6).</pre>