Question 1205725
<pre>
So, my problem is this I solved it once and I got it wrong can you guys help me out?
8x-6y=-2
8x+5y=-13

I am supposed to use the elimination method and get an ordered pair and I am still confused.

8x - 6y = - 2 ------ eq (i)
8x + 5y = -13 ------ eq (ii)

Notice that both equations have IDENTICAL x variables. In order to ELIMINATE ths x-variable and
solve for the other variable (y, in this case), we need to either SUBTRACT eq (i) from eq (ii),
or vice-versa. I chose to do the former.

          8x - 6y = - 2 ------ eq (i)
          8x + 5y = - 13 ----- eq (ii)
              11y = - 11 ----- Subtracting eq (i) from eq (ii)
              {{{highlight_green(matrix(1,5, highlight(y), "=", (- 11)/11, "=", highlight(- 1)))}}}

Now, substitute - 1 for y in either eq (i) or eq (ii). Again, I chose the former.
          8x - 6y = - 2 ------ eq (i)
      8x - 6(- 1) = - 2  ----- Substituting - 1 for y in eq (i)
           8x + 6 = - 2
               8x = - 8
              {{{highlight_green(matrix(1,5, highlight(x), "=", (- 8)/8, "=", highlight(- 1)))}}}

              Finito!!</pre>