Question 1205767


{{{2x-3y=-13}}}.....eq.1=> both sides multiply by {{{3}}}
{{{3x-2y=-7}}}......eq.2=> both sides multiply by{{{ 2}}}
------------------------

{{{6x-9y=-39}}}.....eq.1
{{{6x-4y=-14}}}......eq.2
------------------------subtract

{{{6x-9y-(6x-4y)=-39-(-14)}}}

{{{6x-9y-6x+4y=-39+14}}}

{{{-5y=-25}}}

{{{y=-25/-5}}}

{{{y=5}}}


go to

{{{3x-2y=-7}}}......eq.2, substitute {{{y}}}

{{{3x-2*5=-7}}}

{{{3x-10=-7}}}

{{{3x=10-7}}}

{{{3x=3}}}

{{{x=1}}}


A. One solution:
ordered pair: ({{{1}}},{{{5}}})