Question 1205741

{{{x-5y=32}}}......eq.1
{{{2x+4y=-34}}}.....eq.2
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start with eq.1 and solve for{{{ x}}}

{{{x-5y=32}}}
{{{x=5y+32}}}......eq.1


go to eq.2 and substitute x


{{{2(5y+32)+4y=-34}}}.....eq.2, solve for {{{y}}}

{{{10y+64+4y=-34}}}

{{{14y=-34-64}}}

{{{14y=-98}}}

{{{y=-98/14}}}

{{{y=-7}}}


go to eq.1, substitute {{{y}}}

{{{x=5*(-7)+32}}}......eq.1

{{{x=-35+32}}}

{{{x=-3}}}

answer:  

 A. One solution:

 ordered pair: ({{{-3}}}, {{{-7}}})