Question 1205726
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Picture the diagram as described in the response from tutor @ikleyn.<br>
Then here is a different way you can do the calculations to find the answer to the problem.<br>
Note that the two isosceles right triangles representing the combinations of times when the two students do NOT meet have legs of "length" 35 minutes, or 7/12 of an hour.<br>
Those two triangles put together form a square with side length 7/12 of an hour, so the area of those two triangles together is (7/12)^2 = 49/144 of the total area of the square.<br>
Then the area of the square representing the combinations of times when the two students WILL meet is (144-49)/144 = 95/144 of the total area of the square.  So<br>
ANSWER: The probability that they will meet is 95/144<br>