Question 1205725


{{{8x-6y=-2}}}.....eq.1
{{{8x+5y=-13}}}....eq.2
-------------------------------subtract eq.2 from eq.1 to eliminate {{{x}}}

{{{8x-6y-(8x+5y)=-2-(-13)}}}

{{{8x-6y-8x-5y=-2+13}}}

{{{cross(8x)-6y-cross(8x)-5y=11}}}

{{{-6y-5y=11}}}

{{{-11y=11}}}

{{{y=11/-11}}}

{{{y=-1}}}


go to

{{{8x-6y=-2}}}.....eq.1, substitute {{{y}}}

{{{8x-6(-1)=-2}}}

{{{8x+6=-2}}}

{{{8x=-2-6}}}

{{{8x=-8}}}

{{{x=-8/8}}}

{{{x=-1}}}