Question 1205715


the line that satisfies the given conditions.

through ({{{-5}}}, {{{3}}})
 perpendicular to the line {{{y = -(1/2)x + 9}}}

recall that perpendicular line have slopes negative reciprocal to each other

given line have a slope {{{-(1/2)}}}, so perpendicular line will have a slope {{{m= -1/(-(1/2))=2}}}

using point slope formula

{{{y-y1=m(x-x1)}}}...substitute slope and {{{x1}}} and {{{y1}}}, coordinates of given point


{{{y-3=2(x-(-5))}}}

{{{y-3=2(x+5)}}}

{{{y-3=2x+10}}}

{{{y=2x+10+3}}}

{{{y=2x+13}}}


{{{ drawing( 600, 600, -10, 10, -10, 10, 

circle(-5,3,.12), locate(-5,3,p(-5,3)),
graph( 600, 600, -10, 10, -10, 10,-(1/2)x + 9 ,2x+13)) }}}