Question 1205707
your 2 equations are:


30e + 10c = 470
10e + 30c = 370


multiply the second equation by 3 and leave the first equation as is to get:


30e + 10c = 470
30e + 90c = 1110


subtract the first equation from the second to get:


80c = 640


solve for c to get:


c = 640 / 80 = 8


replace c in the first equation by 8 to get:


30e + 10 * 8= 470
subtract 10 * 8 from both sides of the equation to get:
30e = 470 - 80
simplify to get:
30e - 390
solve for e to get:
e = 390 / 30 = 13


you have c = 8 and e = 13


from the first equation, 30e + 10c becomes 30 * 13 + 10 * 8 = 390 + 80 = 470
from the second equation, 10e + 30c becomes 10 * 13 + 30 * 8 = 130 + 240 = 370


solution of c = 8 and e = 13 is confirmed to be correct.