Question 1205658
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The question appears to have some typos. Please be more careful when posting the question. 


I'll assume the equation is {{{y = 43+x^2}}} in which you can write as y = 43 + x^2


If you want to find y when x = -2, then...
{{{y = 43+x^2}}}
{{{y = 43+(-2)^2}}}
{{{y = 43+4}}}
{{{y = 47}}}



Or if you wanted to find x when y = -2, then...
{{{y = 43+x^2}}}
{{{-2 = 43+x^2}}}
{{{-2-43 = x^2}}}
{{{-45 = x^2}}}
{{{x^2 = -45}}}
If your teacher has not covered imaginary numbers just yet, then the answer is "no real solutions" since squaring a real number does not lead to a negative result.



If your teacher has covered imaginary numbers, and requests the complex roots, then the next set of steps are:
{{{x^2 = -45}}}
{{{x = sqrt(-45)}}} or {{{x = -sqrt(-45)}}}
{{{x = sqrt(-1*9*5)}}} or {{{x = -sqrt(-1*9*5)}}} 
{{{x = sqrt(-1)*sqrt(9)*sqrt(5)}}} or {{{x = -sqrt(-1)*sqrt(9)*sqrt(5)}}}
{{{x = i*3*sqrt(5)}}} or {{{x = -i*3*sqrt(5)}}}
{{{x = 3i*sqrt(5)}}} or {{{x = -3i*sqrt(5)}}}
That can be condensed to
{{{x = "" +- 3i*sqrt(5)}}}
where {{{i = sqrt(-1)}}}
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