Question 1205650
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Find the sum of an infinite geometric series where a1 = 180, and the common ratio is r = 3∕4 
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<pre>
This sum is equal to

    {{{a1/(1-r)}}} = {{{180/(1-3/4)}}} = {{{180/((1/4))}}} = 4*180 = 720.    <U>ANSWER</U>
</pre>

Solved.