Question 1205616
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Answer:  <font color=red size=4>1000 mL (choice D)</font>


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I'll show two methods to solving


Method 1


Batch A = 100% antifreeze
Batch B = 30% antifreeze
Goal is to mix A and B to form a new batch C that is 50% antifreeze.



400 = number of mL of batch A
x = number of mL of batch B
0.30x = number of mL of pure antifreeze from batch B.


m = 400+0.30x = number of mL of pure antifreeze from both batches mixed together.
n = 400+x = total amount of solution (antifreeze plus other chemicals).


m/n = 0.50 to represent getting a 50% solution
(400+0.30x)/(400+x) = 0.50
400+0.30x = 0.50(400+x)
400+0.30x = 200+0.50x
400-200 = 0.50x-0.30x
200 = 0.20x
x = 200/0.20
x = <font color=red>1000 mL is the final answer</font>
The check section is at the bottom.



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Method 2


I'll use the concept of alligation (not to be confused with the word "allegation") which is often used in pharmacy contexts. 


Here's an article talking about it along with some examples
https://en.wikipedia.org/wiki/Alligation


Batch A: 100% antifreeze
Batch B: 30% antifreeze
Target: 50% antifreeze


The gap from A to the target is 50%  (since 100-50 = 50)
The gap from B to the target is 20%  (since 50-30 = 20)
Ignoring the percent signs the ratio of 50:20 reduces to 5:2


It means we have 5 parts of A and 2 parts of B.
Or we might have 5 parts of B and 2 parts of A.
The order at this point isn't clear.


Let's assume it's the first scenario.
If so then
5/2 = 400/x
solves to
x = 160
I'll leave the steps for the student to do.
Luckily this isn't one of the answer choices so we can eliminate this scenario.


But if you didn't have multiple choice answers to rely on, then here's how we can eliminate this scenario.
If we had 400 mL of A and 160 mL of B then we'll have 1*400+0.30*160 = 448 mL of pure antifreeze out of 400+160 = 560 mL total solution.
The ratio is 448/560 = 0.8 which converts to 80% antifreeze instead of the 50% we want.
This is why we can eliminate the first scenario.


The other scenario must be the case.
5/2 = x/400
solves to
x = <font color=red>1000</font>
I'll leave the steps for the student to do.


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Check:


If we had 400 mL of A and <font color=red>1000</font> mL of B then we'll have 1*400+0.30*1000 = 700 mL of pure antifreeze out of 400+1000 = 1400 mL total solution.
The ratio of pure antifreeze to total solution is 700/1400 = 0.50 converting to the 50% solution we want.


The answer is confirmed.


More practice with a similar question can be found here:
https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.1204463.html
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