Question 115781
{{{n-((7)/(n+2))-((3n-1)/(n+2)) }}}
={{{(n(n+2)-7-3n+1)/(n+2) }}} LCD=n+2
={{{(n^2+2n-7-3n+1)/(n+2) }}}
={{{(n^2-n-6)/(n+2) }}}
={{{(n-3)cross(n+2)/cross(n+2) }}}
=n-3
.
The other one is similar. I'll leave it to you.
.
Ed