Question 1205556
{{{log(2,x)-log(2,6)=log(2,5)+2log(2,3)}}}


{{{log(2,x)=log(2,5)+2log(2,3)+log(2,6)}}}

{{{log(2,x)=log(2,5*6)+log(2,3^2)}}}

{{{log(2,x)=log(2,5*6*3^2)}}}


Both logarithm expressions are to base 2, so corresponding expressions are equal too.


{{{x=5*6*3^2}}}----------and you can fully multiply this.
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