Question 1205553
equation is:
2^(4x) = 1/32


take the log of both sides of the equation to get:


log(2^(4x) = log(1/32)


by log rules, this becomes:
4x * log(2) = log(1/32)


solve for 4x to get:
4x = log(1/32) / log(2) = -5


replace 4x in the original equation to get:
2^(-5) = 1/32


2^(-5) is the same as 1/2^5 which is the same as 1/32.


you get 1/32 = 1/32, confirming the solution is correct.