Question 1205534

{{{y=-(5/3)x+2}}}

find {{{x}}} and{{{ y}}}-intercepts

set {{{x=0}}}

{{{y=-(5/3)*0+2}}}

{{{y=2}}}

first ordered pair is ({{{0}}},{{{2}}})

set {{{y=0}}}

{{{0=-(5/3)x+2}}}

{{{(5/3)x=2}}}
{{{x=2/(5/3)}}}
{{{x=6/5}}}

second ordered pair is ({{{6/5}}},{{{0}}})

set {{{x=3}}}

{{{y=-(5/3)*3+2}}}

{{{y=-5+2}}}

{{{y=-3}}}

third ordered pair is ({{{3}}},{{{-3}}})


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(0,2,.12), circle(6/5,0,.12),circle(3,-3,.12),
locate(0.2,2,p(0,2)),locate(6/5,0.4,p(6/5,0)),locate(3,-3,p(3,-3)),

graph( 600, 600, -10, 10, -10, 10, -(5/3)x+2)) }}}