Question 1205489
assumed population profit has a mean of 1200 and a standard deviation of 350.
sample size is 50.
standard error = standard deviation / sqrt(sample size) = 350 / sqrt(50) = 49.49747 rounded to 5 decimal digits.
z-score formula is z = (x-m)/s
z is the z-score
x is the sample mean.
m is the population mean.
s is the standard error.
formula becomes:
z = (1300 - 1200) / 49.49747 = 2.0203 rounded to 4 decimal digits.
area under the normal distribution to the right of that z-score = .0217 rounded to 4 decimal digits.
that's the probability that the mean of the sample of 50 sold honda accord profits will be greater than 1300, assuming the profits are normally distributed.


here are the z-score results on a normal distribution graph.


<img src = "http://theo.x10hosting.com/2023/123001.jpg">


here are the raw score results on the same normal distribution graph.


<img src = "http://theo.x10hosting.com/2023/123002.jpg">


z-score results use a mean of 0 and a standard deviation of 1.

raw score results use the population mean and standard error.