Question 1205455
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The given information gives us the following equation:<br>
{{{load=((k)(width)(depth^2))/length}}}<br>
where k is a constant of proportionality.<br>
We are given the load that can be supported for a given width and depth.  But we are not given the length, so we can't determine the constant of proportionality.<br>
But to solve the problem we don't have to know the value of k.   k is some constant, and in this problem the length is a constant.  So the difference in the load that can be supported is due to putting the bean on its side -- i.e., switching the width and depth.<br>
For the load of 630kg, {{{(width)(depth^2)=(3)(5^2)=75}}}.<br>
When the beam is turned on its side, {{{(width)(depth^2)=(5)(3^2)=45}}}.<br>
So the load that can be supported when the beam is turned on its side is 45/75 = 3/5 of the load it can support in the given configuration.<br>
630*(3/5)=378<br>
ANSWER: 378kg<br>