Question 1205427
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N varies jointly with the square root of p and the cube of q. If n=72 when p=3 and q=2, find n when p=-4 and q=1/2.
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When a problem of this type says that  N  varies jointly as the square root of  "p",

it is usually assumed that  p  is non-negative real number - then the real value  {{{sqrt(p)}}}  does exist.


With negative  "p"  (as  -4  in your question),  square root of negative  "p"  does not exist as a real number.


Therefore,  your problem,  as it is posed in the post,  does not make sense.