Question 1205418

 

let quarters  be {{{q }}}and  dimes {{{d}}}

if Zaire has {{{4}}} times as many quarters as dimes, we have

{{{q =4d}}}....eq.1

if a combined value of ${{{4.40}}},we have

{{{0.25q+0.10d=4.40}}}...eq.2, substitute {{{q}}} from eq.1

{{{0.25*4d+0.10d=4.40}}}....solve for {{{d}}}

{{{1.10d=4.40}}}

{{{d=4.40/1.10}}}

{{{d=4}}}

go to

{{{q =4d}}}....eq.1, substitute {{{d}}}

{{{q =4*4}}}

{{{q =16}}}

Zaire has {{{16}}}quarters and {{{4}}} dimes.