Question 1205403
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I interpret the phrasing "<font color=blue>Suppose your house (E) is opposite the school</font>" to mean "points E and S are on the same vertical line".
{{{
drawing(400,400,-2,8,-3,7,
circle(5,1,0.05),circle(5,1,0.07),circle(5,1,0.09),circle(5,1,0.11),circle(5,1,0.13),circle(5,1,0.15),circle(2,1,0.05),circle(2,1,0.07),circle(2,1,0.09),circle(2,1,0.11),circle(2,1,0.13),circle(2,1,0.15),circle(1,1,0.05),circle(1,1,0.07),circle(1,1,0.09),circle(1,1,0.11),circle(1,1,0.13),circle(1,1,0.15),circle(4,3,0.05),circle(4,3,0.07),circle(4,3,0.09),circle(4,3,0.11),circle(4,3,0.13),circle(4,3,0.15),circle(2,3,0.05),circle(2,3,0.07),circle(2,3,0.09),circle(2,3,0.11),circle(2,3,0.13),circle(2,3,0.15),

line(1,1,2,3),line(2,3,4,3),line(4,3,5,1),line(5,1,1,1),line(2,1,2,3),


locate(0.56,0.84,"H"),locate(1.7,3.22+0.2,"S"),locate(4.28,3.22,"M"),locate(5.24,0.82,"C"),locate(2.06,0.82,"E"),

locate(-2,-2,matrix(1,4,"Diagram","not","to","scale"))
)
}}}
S = school
H = municipal hall
C = church
M = market
E = your house


My drawing is almost the same as tutor Theo's drawing, except point E has been moved to the left to be directly under point S. Also, point D is not needed. 


Recall the area of a trapezoid is:
area = 0.5*height*(base1+base2)
where base1 and base2 are the parallel sides.


In this case, SM = 16 and HC = 22 are the parallel sides.
The goal is to find the distance from your house (E) to your school (S). 
In other words, we want to find the length of segment ES.
But notice that segment ES is the height of the trapezoid.
x = height = length of ES


area = 0.5*height*(base1+base2)
area = 0.5*ES*(SM+HC)
475 = 0.5*x*(16+22)
I'll let the student take over from here.
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