Question 1205358
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In one​ lottery, a player wins the jackpot by matching all five numbers drawn from white balls​ (1 through 51) 
and matching the number on the gold ball​ (1 through 46). What is the probability of winning the​ {{{highlight(cross(minimum))}}} award
{{{highlight(having)}}} {{{highlight(only)}}} {{{highlight(one)}}} {{{highlight(ticket)}}} ?
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        The formulation in the post is incorrect - as in thousands other problems at this forum.


        I fixed/repaired/edited it to make sense from nonsense.


        Below is the solution for the fixed/repaired formulation.



<pre>
In this lottery, the winning configuration is 5 matching numbers from 1 to 51 inclusive 
without looking the order, plus matching 1 number 1 through 46.


There are  {{{C[51]^5}}} = 2349060  different possible combinations of 5 numbers from white balls 
and 46 possible numbers from gold balls.


So, there are 2349060*46 = 108056760 possible different outcomes; of them, only one outcome wins.


Thus the probability to win this lottery having one ticket is  P = {{{1/108056760}}} = 9.2544E-09.    <U>ANSWER</U>
</pre>

Solved.