Question 1205350
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Hint: 
The original equation is of the form
{{{(y-2*sqrt(3))/(y) = (y)/(y+sqrt(3))}}}
where
{{{y = sqrt(3x) + sqrt(3/x)}}}



Another hint:
Solving {{{(y-2*sqrt(3))/(y) = (y)/(y+sqrt(3))}}} for y gets you something of the form {{{y = a*sqrt(b)}}} where 'a' and b are constants and b > 0.
I'll let the student determine 'a' and b.



Final hint:
Plug {{{y = a*sqrt(b)}}} into {{{y = sqrt(3x) + sqrt(3/x)}}} so you can isolate x.
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