Question 1205334
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15000 total part of it at 0.08 per year, the rest at 0.18 per year. 
if received in one year totaled 2000, how much was loaned at 0.08?
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<pre>
x at 0.08; the rest, (15000--x), at 0.18.


Write equation for the annual interest

    0.08x + 0.18*(15000-x) = 2000.


Simplify and solve for x

    0.08x + 0.18*15000 - 0.18x = 2000

    0.08x - 0.18x = 2000 - 0.18*15000

      -0.1x       =   -700

          x       = -700/(-0.1) = 70000.


<U>ANSWER</U>.  7000 at 0.08.
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Solved.