Question 1205297
Solve the equation https://gyazo.com/9c9598aa5e71b13cfbae900cfcb97636 (equation picture link) where 0≤x≤2π
----------------
{{{sin^2(x) - sin(x)/2 - 1/2 = 0}}}
Sub x for sin(x)
{{{x^2 - x/2 - 1/2 = 0}}}
*[invoke solve_quadratic_equation 1,-.5,-.5]
========================
sin(x) = 1
x = 90 degs or pi/2
----
sin(x) = -0.5
x = 210 degs or 7pi/6
x = 330 degs or 11pi/6