Question 115694
{{{log(2,(32))=x}}} Start with the given equation 




{{{2^x=32}}} Rewrite the equation using the property {{{log(b,(x))=y}}} ===> {{{b^y=x}}}


{{{2^x=2^5}}} Rewrite 32 as {{{2^5}}}



Since the bases are equal, the exponents are equal. So x=5


So this means {{{log(2,(32))=5}}}