Question 1205238

{{{STATISTICS}}}

in this case we use formula for permutation which is choosing {{{r}}} things from a set of{{{ n}}} things {{{without}}}{{{ replacement}}}


{{{P(n, r) = n!/(n-r)!}}}


 in this case,  {{{n=10 }}}and {{{r= 4}}}


{{{P(10, 4) = 10!/(10-4)!=5040}}}  different arrangements