Question 1205196

{{{-4x+3y=-14}}}.....eq.1
{{{-2x-4y=-18}}}.....eq.2
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using method of elimination to solve this system

{{{-4x+3y=-14}}}.....eq.1
{{{-2x-4y=-18}}}.....eq.2.....both sides multiply by {{{2}}}

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{{{-4x+3y=-14}}}.....eq.1
{{{-4x-8y=-36}}}.....eq.2
------------------------------subtract

{{{-4x+3y -(-4x-8y)=-14-(-36)}}}.....eq.1

{{{-4x+3y +4x+8y=-14+36}}}

{{{3y +8y=22}}}

{{{11y=22}}}

{{{y=2}}}


go to

{{{-4x-8y=-36}}}.....eq.2, substitute {{{y}}}

{{{-4x-8*2=-36}}}

{{{-4x-16=-36}}}

{{{36-16=4x}}}

{{{20=4x}}}

{{{x=5}}}


solution:

{{{x=5}}}
{{{y=2}}}

intersection point:

({{{5}}},{{{2}}})


{{{ drawing( 600, 600, -10, 10, -10, 10, 
circle(5,2,.12), locate(5,2,p(5,2)),
graph( 600, 600, -10, 10, -10, 10, (4x)/3-14/3, 9/2 - x/2)) }}}