Question 115487
14x - 7 OVER x squared + 3x - 4 TIMES x squared + 6x + 8 OVER 2x squared + 5x - 3 DIVIDED BY x squared + 2x OVER x squared + 2x - 3
:
We can write it:
{{{((14x-7))/((x^2+3x-4))}}}*{{{((x^2+6x+8))/((2x^2+5x-3))}}} / {{{((x^2+2x))/((x^2+2x-3))}}}
:
Remember when you divide fractions, you in invert the dividing fraction & multiply
{{{((14x-7))/((x^2+3x-4))}}}*{{{((x^2+6x+8))/((2x^2+5x-3))}}}* {{{((x^2+2x-3))/((x^2+2x))}}}
:
All the numerators and denominators will factor:
{{{(7(2x-1))/((x+4)(x-1))}}}*{{{((x+2)(x+4))/((2x-1)(x+3))}}}* {{{((x+3)(x-1))/(x(x+2))}}}
Note that almost everything here will cancel leaving you with:
{{{7/x}}}