Question 1205139


a three-digit number:
{{{abc}}}

if the second digit is {{{4}}} times bigger than the third digit, we have 

{{{b=4c}}}

if the first digit is {{{3 }}}less than my second digit, we have

{{{a=b-3}}}

we have digits from {{{0-9}}}

{{{a<>0}}}

{{{a<b}}}

if {{{b=4c }}} than {{{c}}}={{{0}}},{{{1}}},or{{{ 2}}}

since {{{a<b}}},{{{ b=4c}}}  than {{{c}}}={{{1}}},{{{2}}} ({{{0}}} is excluded)

so, {{{b=4*1=4}}} or {{{b=4*2=8}}}

if{{{ b=4 }}}=> {{{a=b-3}}}=> {{{a=4-3}}}=>{{{a=1}}}
or
if {{{b=8 }}}=> {{{a=b-3}}}=> {{{a=8-3}}}=>{{{a=5}}}

since {{{b=4c}}} => {{{c=b/4}}}

if{{{ b=4}}} =>{{{c=1}}}
if{{{ b=8 }}}=>{{{c=2}}}


a three-digit numbers are:

{{{abc=141}}}
or
{{{abc=582}}}