Question 1205128


 
the instantaneous rate of change is a slope , so derivate  {{{h(t)=3sin((pi/8)t)+15}}}

using calculator, you get

{{{h}}}'{{{(t) = (3/8)pi*cos((pi* t)/8)}}}

plug in {{{t=3}}}

{{{h}}}'{{{(t) = (3/8)pi*cos((pi*3)/8)=0.45}}} => answer