Question 1205121
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This set of 4 oldest is a unique set of  {{{C[11]^4}}} = {{{(11*10*9*8)/(1*2*3*4)}}} = 330  different possible sets of 4 from 11.    


Therefore,  P = {{{1/330}}} = 0.00303  (rounded).    <U>ANSWER</U>
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Solved.