Question 1205097

{{{cot(pi/2)=1/tan(pi/2)}}}

since {{{tan(pi/2)=infinity}}}, you have {{{cot(pi/2)=1/infinity}}}

so you need to use identity {{{tan(pi/2)=sin(pi/2)/cos(pi/2)}}}, then you have


{{{cot(pi/2)=1/(sin(pi/2)/cos(pi/2))}}}


{{{cot( pi/2)=cos(pi/2)/sin(pi/2)}}}.....since {{{cos(pi/2)=0}}} and {{{sin(pi/2)=1}}}, you have


{{{cot( pi/2)=0/1}}}

{{{cot( pi/2)=0}}}