<PRE><B>Question 1205085</B>
&lt;br&gt;
The given set is ((AUB)nC)U(BUD)&#39;.&lt;br&gt;
That is the union of two sets, (AUB)nC and (BUD)&#39;.  So any number in either of those two sets is in the given set.&lt;br&gt;
The set (AUB)nC contains exactly the numbers that are in C AND in either A OR B.  From the diagram, those numbers are 4, 5, 6, 8, 9, and 10.&lt;br&gt;
The set (BUD)&#39; contains exactly the numbers that are NOT in the union of B and D -- i.e., all the numbers that NOT in B AND NOT in D.  From the diagram, those numbers are 1, 4, and 7.&lt;br&gt;
Then the given set, which is the union of those two sets, contains the numbers 1, 4, 5, 6, 7, 8, and 9.&lt;br&gt;
The sum of those numbers is&lt;br&gt;
ANSWER: 40&lt;br&gt;
------------------------------------------------------------&lt;br&gt;
After getting a message from the student that my answer was wrong, I looked again and found he is right.  I lost track of the number 10, which is in the set (AUB)nC.&lt;br&gt;
The given set contains the numbers 1, 4, 5, 6, 7, 8, 9, and 10; the sum of those numbers is&lt;br&gt;
ANSWER: 50&lt;br&gt;

</PRE>