Question 1205065
<pre>
It's the probability that a king, a queen, a jack, and the 2 of hearts
come before the other 3 kings, the other 3 queens, and the other 3 jacks.

We are only concerned with the following 13 cards.

K, Q, J, 2 of hearts, K, K, K, Q, Q, Q, J, J, J

The other 39 cards can go anywhere.

We can choose the one king to come before the 2 of hearts 4 ways. 
We can choose the one queen to come before the 2 of hearts 4 ways.  
We can choose the one jack to come before the 2 of hearts 4 ways. 
Those 3 cards can be ordered 3! = 6 ways
The 3 Kings, 3 queens, and 3 jacks that come after the 2 of hearts can be
ordered any of 9! ways.

The number of ways those 13 cards can come in the deck is 13!

So the desired probability is

{{{(4*4*4*3!*9!)/13!}}} that simplifies to {{{16/715}}} or about 0.022

I disagree with all your choices.

Edwin</pre>