<PRE><B>Question 1205049</B>
1.  Area of sector - area of triangle = area of shaded portion

CM = 16* sin 27.5 degrees =7.3879*2=14.775

OM = 16* cos 27.5 degrees =14.19

Area of triangle = 1/2 *14.775*14.19=104.828 cm^2

Area of sector = {{{((theta)/360)*pi*r^2}}}



 = {{{((55)/360)*pi*16^2}}}=122.87 cm^2



122.87-104.828= 18.042 cm^2 approx Area of shaded portion.



OR you can directly use the formula given below



A = {{{(1/2) *r^2* ((pi*(theta)/180) -sin (theta))}}}



A=5*256*((pi*55/180)-sin55degrees)



*[illustration segment.png].

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