Question 1205038


Convert the given Cartesian coordinates to polar coordinates with

{{{r > 0}}}, {{{0 <= theta <= 2pi}}}

({{{6}}}, {{{4}}})


Polar Coordinates ({{{r}}},{{{theta}}}): 

{{{r = sqrt( x^2 + y^2 ) }}}
{{{r = sqrt( 6^2 + (-4)^2 ) }}}
{{{r = sqrt( 36 + 16 ) }}}
{{{r = sqrt( 52 ) }}}
{{{r=2sqrt(13)}}}


{{{theta = tan^-1 ( y / x )}}}
{{{theta = tan^-1 ( -4 / 6 )}}}
{{{theta = tan^-1 ( -2 / 3 )}}}
{{{theta = -33.69}}}°

angle is in quadrant {{{4}}}

 ({{{r}}},{{{theta}}})= ({{{2sqrt(13)}}},{{{-33.69}}}°)

or, approximately

 ({{{r}}},{{{theta}}})= ({{{7.2}}},{{{-33.69}}}°)