Question 1205031
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Obviously there is a typo -- p can't vary directly as the square of p.<br>
Equally obviously, as the problem is presented, the intent is that p varies directly as the square of q.<br>
Given that, here is my choice of how to solve this kind of problem.<br>
p varies directly as the square of q.  In the given scenario, q=4.30, and in the new scenario q=5.40.  Since p varies as the square of q, this increase in the value of q causes the value of p to increase by a factor of (5.40/4.30)^2.<br>
p varies inversely as the cube of r.  In the given scenario, r=2.95, and in the new scenario r=2.84.  Since p varies inversely as the cube of r, this decrease in the value of r causes the value of p to increase by a factor of (2.95/2.84)^3.<br>
Find the new value of p by multiplying the value of r in the given scenario by these two factors.<br>
{{{p=(13.013)((5.40/4.30)^2)((2.95/2.84)^3)}}}<br>
which evaluates to 23, correct to 3 decimal places.<br>
ANSWER: 23<br>